0=16t^2+175t-85

Solution for 0=16t^2+175t-85 equation:

0=16t^2+175t-85

We move all terms to the left:

0-(16t^2+175t-85)=0

We add all the numbers together, and all the variables

-(16t^2+175t-85)=0

We get rid of parentheses

-16t^2-175t+85=0

a = -16; b = -175; c = +85;
Δ = b2-4ac
Δ = -1752-4·(-16)·85
Δ = 36065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-175)-\sqrt{36065}}{2*-16}=\frac{175-\sqrt{36065}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-175)+\sqrt{36065}}{2*-16}=\frac{175+\sqrt{36065}}{-32}
$